Corrigé du 29 P. 136
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1. $P(C) = \dfrac{406+591}{1500} = \dfrac{997}{1500} \approx 0,665$.
2. $P_C(S) = \dfrac{402}{402+591} = \dfrac{402}{993} \approx 0,405$.
3. $P(\overline C \cap S) = \dfrac{315}{1500} = 0,21$.