Corrigé du 36 P. 22

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\[\begin{aligned} v_0 &= 4\;;& \\ v_1 &= 3v_0 - 1 = 3\times 4 - 1 = 11\;;& \\ v_2 &= 3v_1 - 1 = 3\times 11 - 1 = 32\;;& \\ v_3 &= 3v_2 - 1 = 3\times 32 - 1 = 96 - 1 = 95\;;& \\ v_4 &= 3v_3 - 1 = 3\times 95 - 1 = 285 - 1 = 284.& \end{aligned}\]

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